Arithematic progression
EXERCISE 5.1 1. In which of the following situations, does the list of numbers involved make an arithmetic progression, and why? (i) The taxi fare after each km when the fare is Rs 15 for the first km and Rs 8 for each additional km Solution: The fare for first km = 15 the taxi fare after completing 1st km=8 always, fare=(number of km travelled)×(cost for each km), Therefore, fare for 1st km=15 =15 fare for 2nd km=15+8 =23 fare for 3rd km=15+(2×8) =31 fare for 4th km=15+(3×8) =39 a1=15 a2=23 a3=31 a4=39 d1=a2-a1=23-15=8 d2=a3-a2=31-23=8 d3=a4-a3=39-31=8 since d1=d2=d3 there above sequence is in ap The same problem is solved in Youtube https://youtu.be/oXGPpZXDxZI The same problem is solved handy or with hand in the following link https://mytextbookexercise.blogspot.com/2019/05/exercise-5.html (ii) The...